Calculate he length of second's pendulum on the surface of moon when acceleration due to gravity on moon is 1.63m/s
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Time period of pendulum = 2π√(l/g)
Since account due to gravity= 1.63m/s^2
2= 2π √(l/1.63)
Or
1.63/l = π×π
L=1.63/π^2
L=0.1651 m
L=16.51cm
Since account due to gravity= 1.63m/s^2
2= 2π √(l/1.63)
Or
1.63/l = π×π
L=1.63/π^2
L=0.1651 m
L=16.51cm
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