Physics, asked by kchowdary857, 7 months ago

Calculate heat energy required to change 12g of ice at -10°c into water vapour at100°c.​

Answers

Answered by sattibabuchelluri131
1

Answer:

8700 calories

Explanation:

Latent heat of fusion =80cal/gm

Latent heat of vaporisation=540cal/gm

-10℃ ice........0℃ice.....0℃water.....100℃water.....100℃watervapour

(12×0.5×10)+(80×12)+(12×1×100)+(540×12) =8700 cal

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