Calculate heat energy required to change 12g of ice at -10°c into water vapour at100°c.
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Answer:
8700 calories
Explanation:
Latent heat of fusion =80cal/gm
Latent heat of vaporisation=540cal/gm
-10℃ ice........0℃ice.....0℃water.....100℃water.....100℃watervapour
(12×0.5×10)+(80×12)+(12×1×100)+(540×12) =8700 cal
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