Calculate height of table,and distance between cat and tortoise puzzle
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you didn't attach figure. figure is attached as you can see.
Let height of table is x
height of cat is y
height of tortoise is z .
case 1 :- height of cat + height of table - height of tortoise = 170cm
y + x - z = 170 ........(1)
case 2 :- height of tortoise + height of table - height of cat = 130cm
z + x - y = 130........(2)
adding equations (1) and (2),
y + x - z + z + x - y = 170 + 130
2x = 300 => x = 150
hence, height of table is 150cm.
[note :- may be it's not your solution . but 70-80% chances solution of your question is given above, if you give complete explanation, we must add a brief explanation of your complete question. ]
Let height of table is x
height of cat is y
height of tortoise is z .
case 1 :- height of cat + height of table - height of tortoise = 170cm
y + x - z = 170 ........(1)
case 2 :- height of tortoise + height of table - height of cat = 130cm
z + x - y = 130........(2)
adding equations (1) and (2),
y + x - z + z + x - y = 170 + 130
2x = 300 => x = 150
hence, height of table is 150cm.
[note :- may be it's not your solution . but 70-80% chances solution of your question is given above, if you give complete explanation, we must add a brief explanation of your complete question. ]
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2
The question is incomplete without the figures.
However,
Considering the figures,
Inferences from the first picture:
Height of the table + cat - tortoise = 170
Inferences from the second picture:
Height of the table - cat + tortoise = 130
Let us consider the height of the table, cat and tortoise to be x, y and z respectively.
Hence we get,
x+y-z=170
x-y+z=130
Equating both the equations:
By addition,
x+y-z=170
x-y+z=130
We get,
Height of two tables = 170 + 130
Height of two tables = 300 cm
Therefore,
Height of one Table = 300 ÷ 2 = 150 cm
Hence, the height of the table is 150 cm.
The distance between the cat and the tortoise cannot be determined with the data available.
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