Question

calculate how many atoms of carbon are present in 0.18g of ethanedioic acid

Answer 1

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Clarie S.

 asked • 02/05/21

How many carbon atoms are in 44g H2C2O4?

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Richard P. answered • 02/05/21

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The molar mass of this compound is 58 g. Hence 44g amounts to .7586 moles.

One mole of this compound contains 2 x N0 (where N0) is the Avagadro number) of carbon atoms.

This works out be be 9.133 x 1023

Answer 2

Let us recall the concept of the mole concept.

given values are-

given mass of ethanedioic acid= 0.18 gm

molecular mass ethanedioic acid = $C_{2} O_{4} H_{2}$

                                                       = 2×12+16×4+1×2

                                                       = 90 gm.

number of moles= $\frac{given mass}{molecular mass}$

                           =$\frac{0.18}{90}$

                           = 0.002 moles

number of atoms of carbon= no of atoms of carbon×no of moles×Avogardo number($N_{A}$)

                                            =2×0.002×6.02×$10^{23}$

                                             = 24.08×$10^{23}$

the final answer is 24.08×$10^{23}$ atoms of carbon are present in 0.18 gm of ethanedioic acid.