Question

Calculate how many moles of sulphur dioxide will be evolved when
5 moles of sulphur is reacted with oxygen.​

Answer 1

Moles of sulphur dioxide evolved when 5 moles of sulphur is reacted with oxygen is 5 moles.

The reaction when sulphur reacts with oxygen to give sulphur dioxide is :--

S(g) + O2(g)---------> SO2(g)

As per stoichiometry  1 mole of sulphur reacts with 1 mole of oxygen to give 1 mole of sulphur dioxide.

Hence 5 mole of sulphur reacts with 5 mole of oxygen to give 5 mole of sulphur dioxide.

Mass of 1 mole of SO2 = 64grams.

So 5 mole SO2 has 5*64 grams of SO2= 320grams of  SO2.

Hence amount of SO2 evolved is 320 grams or 5 moles.

Answer 2

So, 5 moles of sulpher dioxide will be evolved whe 5 mole of sulpher is reacted with oxygen.

Explanation:

Reaction of sulphur and oxygen is

S+O₂--------> SO₂

5S+ 5O₂⇔5SO₂

So, 5 moles of sulpher dioxide will be evolved whe 5 mole of sulpher is reacted with oxygen.