calculate how much lime will be obtained by heating 500g of lime stone of 50%purity? (ca=40,C= 12,O=16)
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We have to calculate the amount of line obtained by heating 500g of lime stone of 50% purity.
solution : chemical formula of lime stone is CaCO3 and lime is CaO
when lime stone is heated, carbon dioxide evolves and lime is formed.
i.e., CaCO3 => CaO + CO2
here you see 1 mole of lime stone forms 1 mole of lime. ....(1)
given mass of lime stone is 500 but purity of it is 50%
so mass pure lime stone = 50 % of 500 = 250 g
now no of moles of lime stone = 250g/100g/mol = 2.5 mol [ molecular mass of CaCO3 is 100g ]
from equation (1),
we can say that no of mole of lime will be formed = 2.5 mol
so mass of lime = 2.5 × molecular mass of Lime
= 2.5 mol × 56 g/mol
= 140 g
Therefore the amount of lime will be obtained is 140g.
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