calculate how much volume of 8g.hydrogen gas occupies at STP
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1mol of a gas at STP occupies 22.4L
1mol of a gas at STP occupies 22.4LIn this case, we have 8g of hydrogen at STP, which is 8g/2g/mol = 4mol
1mol of a gas at STP occupies 22.4LIn this case, we have 8g of hydrogen at STP, which is 8g/2g/mol = 4molSo, at STP, 4mol of hydrogen occupies 4x22.4 = 89.6L
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