Question

Calculate:
(i) The amount of each reactant required to produce 750 ml of carbon
dioxide, when two volumes of carbon monoxide combine with one
volume of oxygen to produce two volumes of carbon dioxide.
2CO + O2 → 2CO2
(ii) The volume occupied by 80 g of carbon dioxide at STP.
(iii) Calculate the number of molecules in 4.4 gm of CO2.
[Atomic mass of C= 12, O=16]
(iv) State the law associated in question no. (f) (i) above.
​

Answer 1

Answer:

(i) = 750 ml of CO and 375 ml of O2 reacts to produce 750 ml of CO2

(ii) 1.82 L (approx)

(iii) 0.1 mol

(iv) Avogadro's law

Explanation:

(i)

Equal moles of gases at same temperature and pressure occupy equal volumes;

If 2 moles of CO

and 1 mole of O2

React

to form 2 moles of CO2

moles of CO and CO2 are equal so volumes are also equal.

so ,

volume of CO = 750 ml;

moles of O2 is half of volume of CO2 .

so,

volume of O2 = 750/2

                       = 375 ml;

(ii)

we know,

1 mole of gas at STP occupy 1L volume;

molar mass of CO2 = 12 + 2*16

                                = 12 + 32

                                = 44 g

1 mole of CO2 = 44 g;

So,

44 g CO2 occupy 1L volume;

then to find volume occupied by 80 g of CO2 :-

= 80*1 / 44

= 1.82 L (approx)

(iii)

Already solved

1 mol of CO2 = 44 g;

then to find moles in 4.4 g of CO2 :-

= 4.4 / 44

= 0.1 mol

(iv)

In eg. (i) we use Avogadro's law,(also known  as Avogadro's hypothesis or Avogadro's principle),

It states that,"equal volumes of all gases, at the same temperature and pressure, have the same number of molecules(i.e. moles)."

Answer 2

Answer:

(i) 750 ml of CO and 375 ml of O2 reacts to produce 750 ml of CO2

(ii) 1.81 L

(iii) 0.1 mol

(iv) Avogadro's law

Explanation:

(i) equal volumes are occupied by equal moles of gases at the same temperature and pressure;

2 moles of CO

plus 1 mole of oxygen

React

create two moles of CO2

moles of CO and CO2 are equal so volumes are also equal.

so,

volume of CO = 750 ml;

moles of O2 is half of the volume of CO2.

so,

volume of O2 = 750/2

                      = 375 ml;

(ii) 1 mole of gas at STP occupies 1L volume;

molar mass of CO2 = 12 + 2*16

                               = 12 + 32

                               = 44 g

1 mole of CO2 = 44 g;

So,

44 g CO2 occupy 1L volume;

then to find the volume occupied by 80 g of CO2:-

= 80*1 / 44

= 1.81 L

(iii) 1 mol of CO2 = 44 g;

then to find moles in 4.4 g of CO2:-

= 4.4 / 44

= 0.1 mol

(iv) Avogadro's law, sometimes referred to as Avogadro's hypothesis or Avogadro's principle, states that "identical volumes of all gases, at the same temperature and pressure, have the same number of molecules (i.e. moles)" in example 

To learn more about avogadro's law from the given link

https://brainly.in/question/1782272

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