Calculate ∧[infinity] HOAc
L¥ using appropriate molar conductances of
the electrolytes listed above at infinite dilution in H₂O at
25°C
(a) 217.5 (b) 390.7
(c) 552.7 (d) 517.2
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The conductance of the electrolytes listed above at infinite dilution in H₂O at 25°C is HOAc ∞ = 390.7 S cm^2 mol −1
Option (B) is correct.
Explanation:
HCl + NaOAc ⟶ NaCl + HOAc
Now
HOAc ∞ = Δ NaOAc∞ + ΔHCl ∞ − Δ NaCl ∞
HOAc ∞ = (91.0 + 426.2 − 126.5) S cm^2 mol −1
HOAc ∞ = 390.7 S cm^2 mol −1
Thus the conductance of the electrolytes listed above at infinite dilution in H₂O at 25°C is HOAc ∞ = 390.7 S cm^2 mol −1.
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