Question

calculate ionic strength of 0.15molal kcl solution​

Answer 1

Answer:

1. I=\frac{1}{2}\sum ^{n}_{i=1}c_{i}z^{2}_{i}

2. Here, half the term ½ is because we consider both the ions as cation and anion. ...

3. Answer- First of all, the dissociation will be KCL\rightarrow K^{+}+Cl^{-}.