Question

Calculate ‘J’ with following observation: Voltmeter reading, V1 = 12 V V2 = 11.5 V Ammeter reading, I1 = 3.0 amp I2 = 2.8 amp Mass of water, m1= 150.51 gm m2 = 99.53 gm Time, t = 120 sec Temperature T1 = 7 ○C T2 = 9.5 ○C​

Answer 1

Answer:

V

1

and V

2

are equal and out of phase with each other and thus get cancelled. Thus V

3

=220V and i=

100

220

=2.2A