Calculate K, if the partial pressures of reactants
and products in the dissociation of 1 mole of
phosphorous pentachloride are 0.3 atm, 0.4 atm
and 0.2 atm respectively.
Answers
Answered by
0
Answer:
PCl
5
⇋
K
p
PCl
3
+Cl
2
K
C
=
[PCl
5
]
[PCl
3
][Cl
2
]
,
Equilibrium constant of reaction remain same.
K
P
=
[P
PCl
5
]
[P
PCl
3
][P
CL
2
]
K
P
=
0.6
(0.3)(0.2)
=0.1,
Now as concentrations are doubled for PCl
3
and Cl
2
K
p
=0.1=
[PCl
5
]
(0.6)(0.4)
⟹P
PCl
5
=2.4
Hence, the correct option is C.
Explanation:
copied answer from google sab te hi karte he
Similar questions