Question

calculate kb for a monoacidic base whose 0.10m solution has ph of 10.50

Answer 1

Answer:

First let's calculate [H+] in mol L^-1.

a. 1% means alpha= 0.01.

b. for mono acidic base say BOH, [OH-]= 0.01× 0.001 =1×10^–5

c .At 298 K [H+] ×[OH-] = Kw = 1×10 ^-14 ,[H+]=1×10^-9