Question

Calculate Kc at 1000ºC for the following reaction:
C(s) + CO2(g) <=> 2CO(g)
Knowing that at equilibrium at the same temperature in a container of 10.0L you have 0.300 moles of CO2 and 1.87 moles of CO.

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Is it possible to solve this problem by finding the moles of C in the following way:
Cn/V + CO2n/V = 2COn/V [divided everything by the volume]
Cn + 0.300 = 2*1.87
Cn = 2*1.87/0.300

Answer 1

Answer: 1.16

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

So equilibrium constant will be:

$K_{c}=\frac{[CO]^2}{[CO_2]}$

where [] represents concentration which is moles dissolved per unit volume.

$K_c=\frac{\frac{1.87}{10}^2}{\frac{0.300}{10}}$

$K_c=1.16$

The equilibrium constant will be 1.16.