Chemistry, asked by Rosh3021, 1 month ago

Calculate kinetic energy of 2&5 moles of nitrogen at 27*c

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Answered by s02371joshuaprince47

0

Answer:

We have kinetic energy = 3/2 nRT. Temperature in Kelvin = 273k+27°C = 300K.

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Answered by sohamshinde507

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