Calculate kinetic energy of 2moles of nitrogen 2 at 27° Celsius?
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According to Kinetic theory of gases, Kinetic Energy of a gas at given temperature is
K.E.=32nRTK.E.=32nRT
Where
nRT=no. of moles of gas=Universal gas constant=Temperature(K)n=no. of moles of gasR=Universal gas constantT=Temperature(K)
Therefore, Kinetic Energy of 4 moles of Nitrogen gas at 127°C(400K) will be
K.E.=32nRTK.E.=32nRT
Where
nRT=no. of moles of gas=Universal gas constant=Temperature(K)n=no. of moles of gasR=Universal gas constantT=Temperature(K)
Therefore, Kinetic Energy of 4 moles of Nitrogen gas at 127°C(400K) will be
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