Question

Calculate kinetic energy of 3 moles of CO2 gas at 27°C

The one answers first will be marked as brainlist​

Answer 1

Explanation:

k=3nRT÷2

given n=3

t=27℃=300k

R=2calories

then. K=3×3×2×300÷2

K=2700calories=2.7kcal