Question

calculate kinetic energy of 5 moles of an ideal gas at 27°C

Answer 1

Kinetic energy = {3*n*R*T} / 2

where, 

n = number of moles

R = gas constant

T = temperature in kelvin

We have above is, n = 5 moles of N

R = 8/314, 

and T = 27 + 273 (to convert celsius to kelvin, add 273)=300. 

Kinetic energy = {3*5*8.314*300} / 2

= 18,706.05 joules or 18.706 kj