Question

Calculate kinetic energy of helium molecules in 1 cm^3 at pressure of 2 atmospheres.
[1 atmosphere= 1.013×10^5 N/m^2]​

Answer 1

Explanation:

kinetic energy of 8 litres

Answer 2

Give : Volume= 1cm^3, pressure= 2atm

To find: Kinetic energy

Solution: We know that helium molecules are constantly in motion and are colliding with each other and with the walls of the container.

We also know that, Kinetic energy= 3KT/2= 3RT/2

in which T is temperature amd R is constant.

According to the idea gas equation: PV= RT

therefore we can say that K.E.= 3PV/2

where p is pressure exerted by helium gas molecules

V is volume occupied

K.E.=( 3× 2×( 1.013×10^5)× (10^-2)^3)/2

K.E.= 0.3039J

Therefore, the kinetic energy of helium molecules will be 0.3039J.