Calculate kp at 900 k where the equilibrium steam hydrogen mixture was 45%h2 by volume
Answers
Answered by
61
Answer:
Explanation:
Kp=[H2SO4]*2/[H2]*2
=60%/40%
=0.6/0.4
=2.25
Answered by
0
Answer -
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- 2H2O(g) + Sn(l) at 900 K the equillibrium steam hydrogen mixture. and liquid states compounds would not take part in Kc or Kp. Hence Fnal volume becomes.
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