Question

Calculate LCV of a fuel which has 8.9 % hydrogen and its HCV is 6500 Cal/g Given latent heat of steam is 580 Cal/g.​

Answer 1

Answer:

formula Q=mc∆T

here c = 540+80=620

put the value if the ans the answer is correct then the way is correct

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Answer 2

Answer:

LCV = 6035.42 Cal/g

Explanation:

Given,

High calorific value, HCV = 6500 Cal/g.

Latetnt heat of steam = 580 Cal/g.

Weight of hydrogen = 8.9%

Lower calorific value, LCV =?

So, according to Dulong's formula ,

LCV = HCV -[ ( weight of hydrogen in %/100) × 9 × latent heat of steam]

so,

$LCV = 6500 - [(\frac{8.9}{100} ) * 9 * 580]$

$LCV = 6500 - (0.089 * 9 * 580)$

$LCV = 6500 - 464.58$

LCV = 6035.42 Cal/g.

RESULT: Lower calorific value (LCV) IS 6035.42 Cal/g.