Question

Calculate length of second pendulum at a place where value of g = 9.75m\s2

Answer 1

Explanation:

In this way we can solve your problem my friend

Answer 2

Answer:

The length of a seconds pendulum at a place where $g=9.75m/s^{2}$ is $l=0.989m$

Explanation:

The seconds pendulum is a type of pendulum whose time period is exactly two seconds $T=2s$

For a normal pendulum time period is

$T=2\pi \sqrt{\frac{l}{g} }$

By rearranging the terms to get the length of a seconds pendulum with point mass attached to a weightless string of length $l$ is

$4=4\pi ^{2}l/g\\l=g/\pi ^{2}$

from the question, have acceleration due to gravity is $g=9.75m/s^{2}$

therefore the length of the seconds pendulum is $l=9.75/9.85=0.989m$