Question

calculate log 6.2 without using
log table​

Answer 1

Given:

$\bold{\log 6.2}$

To find:

Find the value of $\log 6.2$ without log table.

Solution:

some important log values:

$\log 2 = 0.301\\\log 3 = 0.477\\\log 5 = 0.699\\\log 7 = 0.845$

equation:

$\Rightarrow \log 6.2\\\\\Rightarrow \log (6+0.2)\\\\\Rightarrow \log (6)+\frac{0.2}{2.42 \times 6}\\\\\Rightarrow \log (3 \times 2)+\frac{0.2}{2.42 \times 6}\\\\\Rightarrow \log (3) + \log(2)+\frac{0.2}{2.42 \times 6}\\\\\Rightarrow \log (3) + \log(2)+\frac{0.2}{14.52}\\\\\Rightarrow \log (3) + \log(2)+ 0.013\\\\\ put \ the \log \ values:\\\\\Rightarrow 0.477+0.321+0.013\\\\\Rightarrow 0.791$

The final value is: "0.791"