calculate longest wavelength that can be obtained in the Balmer series of H atom
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2
Answer:
Hey mate here is ur answer
Step-by-step explanation:
656.93 is ur answer
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Answered by
52
Answer:
transition should be from orbit 3 to 2
1/A = R ×1^2 ((1/2^2)-(1/3^2))
A is wavelength
R is rhydberg constant ( you can use 1/R =912 Angstrom)
it will make calculation convenient
Step-by-step explanation:
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