Calculate magnetic energy required to build up the current I in a coil of self inductance L
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Answer:
Self Inductance of a coil is the magnetic flux linked with the coil when the current through coil is IA
ϕ=li where L is the constant of proportionality .
Let a source of emf be connected to an inductor L
With increase in current ,the opposite emf ,e=−L
dt
di
Work done dw=∣e∣idt=Li
dt
di
dt=Lidi
W=∫
0
i
Lidi=
2
1
Li
2
Energy stored in magnetic inductor,U=
2
1
Li
2
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