Question

Calculate magnetic moment of fe2+(aq) io (z=26)

Answer 1

Given that,

An ion Fe²⁺.

To find,

The magnetic moment.

Solution,

Fe²⁺ is an ion. Its electronic configuration is $1s^22s^22p^63s^23p^63d^64s^0$

It is clear that the total number of unpaired electrons are 4.

The formula used to find the magnetic moment is given by :

$\mu=\sqrt{n(n+2)} \\\\\mu=\sqrt{4\times (4+2)} \\\\\mu =4.89\ \text{B.M.}$

So, the magnetic moment of Fe²⁺ is 4.89 B.M.