Question

calculate mass 12.046 x 10^23 of glucose

Answer 1

Explanation:

Molecular mass for Glucose ( C6H12O6) is

=(12×6+1×12+16×6)

=72+12+96

=180

Converting the mass into Gram(C.G.S) =

180 g

So,we know that,

$6.023 \times {10}^{23} number \: of \: glucose \: contain \: 180g$

so,1 number contain

$\frac{180}{6.022 \times {10}^{23} }$

so,12.046×10^ 23 contains=

12.046/6.023× 180 = 360 g of Glucose