calculate mass and molecule present in 44.8L of CO
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Answer:
Explanation:Pressure= 2 atm
temperature= 273K
volume= 44.8cm
3
=44.* litre
so,By PV=nRT
n=
RT
PV
mole=
0.0821×273
2×44.8
so, no of moles= 3.998=4
hence, 4×6.023×10
23
=24.08×10
23
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Answer:
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