Calculate mass and number of molecules of sodium that is required to convert
TiCl4 to 88gms of Ti? (At.wt of Ti=44, At wt of Na =23)
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Given:
- Atomic weight of Ti = 44.
- Atomic Weight of Na = 23.
To find:
- Mass and molecules of Na required to convert TiCl4 to 88 gm of Ti.
Solution:
- TiCl₄ + 4Na ⇒ Ti + 4NaCl
- We need 88 gm of Ti i.e 2 moles. So multiplying above equation by 2.
- 2TiCl₄ + 8Na ⇒ 2Ti + 8 NaCl.
- We can observe that 8 moles of Na is required.
- Weight of 1 mole Na = 23 grams is given.
- 8 moles of Na = 8*23 = 184gm.
- 184 grams or 8 molecules of Na are required.
Answer:
- 8 moles or 184 grams of Na is required to convert TiCl₄ to 88 gm of Ti.
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