Calculate mass of 2.4088 * 10^24 atoms of nitrogen
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mass of 2.4088 * 10^24 atoms of nitrogen is 54.6
Explanation:
Given
atoms of nitrogen = 2.4088 X 10²⁴ atoms
mass = ??
Solution
first need to calculate moles
Number of atoms = No. of Moles X Avogadro's number
No. of Moles = Number of atoms/ Avogadro's number
No. of Moles = 2.4088 X 10²⁴/ 6.022 X 10²³
No. of Moles = 3.9 mol
for mass
No. of Moles = mass in grams/ Atomic mass
mass in grams = 3.9 X 14
mass in grams = 54.6 g
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