Question

Calculate mass of 2.4088 * 10^24 atoms of nitrogen

Answer 1

mass of 2.4088 * 10^24 atoms of nitrogen is 54.6

Explanation:

Given

atoms of nitrogen = 2.4088 X 10²⁴ atoms

mass = ??

Solution

first need to calculate moles

Number of atoms = No. of Moles  X Avogadro's number

No. of Moles = Number of atoms/ Avogadro's number

No. of Moles = 2.4088 X 10²⁴/ 6.022 X 10²³

No. of Moles = 3.9 mol

for mass

No. of Moles =  mass in grams/ Atomic mass

mass in grams = 3.9 X 14

mass in grams = 54.6 g