Question

Calculate mass of 90percent pure mno2 to proudce 35.5

Answer 1

Answer:

Explanation:

the amount of the iodine liberated (Mn = 55, Cl = 35.5, I =127)

 0

MnO2 + 4HCl → Cl2 + MnCl2 + 2 H2O

One mole, i.e. 87g of MnO2​ react to form one mole, i.e 71 g of Cl2.

So 8.7 g will form 7.1 g of Cl2.

​Cl2 + 2KI → 2KCl + I2

​One mole, i.e. 71 g of Cl2​ react to form one mole, i.e 254 g of I2.

So 7.1 g will form 25.4 g of I2.