Question

Calculate mass of a solute in 1000cc solution (1 litre) at 298K having osmotic pressure 2.)
The solution Mg = 36.95. R = 0.0821 litre atm K^-1 mol^-1​
plz solve it . plz

Answer 1

Answer:M is 41.66 mol/g

I hope you understand

Answer 2

Mass of solute = 3.0205g

We konw : $\pi$V = nRT    ,   where $\pi$ is Osmotic pressure, V is volume of the solution, n is number of moles of solute in the solution, R is Rydberg constant, T is temperature.

Now, $\pi$ = nRT/V

• From given data, R = 0.0821 Latm/Kmol, T = 298K , V = 1L, $\pi$ = 2 atm
• This implies,                                                                                                        2 = n * 0.0821 * 298 / 1    
• n = 2 / 0.0821 * 298
• n = 2 / 24.4658
• n = 0.08175 M
• Now, we know number of moles of solute ,                                                  n = Mass of solute in the solution / Molar mass of solute
• Also given Molar mass of solute M = 36.95 g
• This implies ,  n = x / M              where x is mass of solute.
•     0.08175 = x / 36.95
•     x = 36.95 * 0.08175
•     x = 3.0205g
• Therefore, mass of solute is 3.0205g.