Question

Calculate mass of ca which contain the same no of atoms as are present in 3.2gms of sulphur

Answer 1

Number of atoms in 1 mole of an element = 6.023 x1023. So, 32 g of S contains 6.023x1023 atoms. Therefore, 3.2 g of S will contain ( 6.023x1023 x 3.2)/32 = 6.023x1022 atoms of S. Now, weight of 6.023x1023 atoms of Ca is 40 g