Question

calculate mass of glucose required to contain 7.2*10^26 atoms of oxygen
pls do by your self i want your method of doing

Answer 1

Answer:

mf of glucose is C6H1206

HENCE if it contains 7.2*10^26 atoms of oxygen, it will have double the atoms of hydrogen and equal atoms of carbon

thus its mass will be 7.2*10^26*14+14.4*10^26*1+7.2*10^26*16=230.4*10^26amu

Answer 2

Explanation:

1.First we have to calculate no of molecules.

no of molecules=7.2×10^26 ÷ 6

=1.2×10^26

2.now we have to calculate no of moles.

no of moles= no of molecules÷

avagadro const

=1.2×10^26 ÷ 6×10^23

=0.2×10^26 ÷10^23

=200

no of moles=200

3.now we calculate mass

Mass=molar mass of glucose×no of

moles

=180 ×200

=36000g or 36 kg

Mass of glucose is 36 kg.

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