Question

calculate mass of glucose required to contain 7.2×10^26 atoms of oxygen​

Answer 1

Answer:

number of atoms of oxygen =7.2×10^26

atomic mass of oxygen = 16

no.of atoms =

(mass/ atomic mass )×avogadro no.

7.2×10^26 = (mass/ 16)×6.023×10^23

mass = (7.2×10^26/6.023×10^23)×16

mass of oxygen = 19.2×10^3 g.

180g of glucose contain 96g of oxygen.

then,

19.2×10^3 g of oxygen is present in

( 180×19.2×10^3)/96

=36g

hence 36g of glucose contain 7.2×10^26 atoms of oxygen.