calculate mass of H2SO4 required to neutralize 11.2gm of KOH
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Answer:
The atomic mass of H
2
SO
4
=98 g/mol
The number of moles of H
2
SO
4
in 196 grams =
98g/mol
196g
=2 moles
1 mole of H
2
SO
4
will be neutralized by 2 moles of KOH.
H
2
SO
4
+2KOH→K
2
SO
4
+2H
2
O
Hence, 2 moles of H
2
SO
4
will be neutralized by 4 moles of KOH.
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