Question

Calculate mass of KCl that is produced from 1 mole of KClO3 if % of field of
reaction is 80%.
1) 59.6gm
2) 50gm
3) 69.6gm
4) 49.5gm​

Answer 1

Answer: 1) 59.6gm

Explanation:

$2KClO_3\rightarrow 2KCl+3O_2$

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles

According to stochiometry:

2 moles of $KClO_3$ produce 2 moles of KCl.

2 moles of $KClO_3$ produce $=2\times 74.5=149g$ of KCl.

Thus 1 mole of $KClO_3$ produce $=\frac{149g}{2}\times 1=74.5 g$ of KCl.

But as % yield of the reaction is 80%, the amount of $KCl$ produced is=$\frac{80}{100}\times 74.5=59.6g$