calculate mass of Na which contains same no. of atoms as there are atoms in 270 grams of Al
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good stoichiometry review before the AP in May!
Assuming we’re talking solely about elemental calcium and magnesium, the calculations are as follows:
8.0 g Ca / 40.08 g/mol (molar mass of calcium) = 0.20 mol Ca
0.20 mol * 6.02^23 atoms/mol (Avogadro’s number) = 1.2 * 10^23 atoms of calcium in your sample.
Now for the magnesium, we just work backwards:
1.2*10^23 atoms of magnesium = 0.20 mol Mg (this doesn’t change).
0.20 mol * 24.31 g/mol (molar mass of magnesium) = 4.9 g Mg.
So the answer to your question is 4.9 g Mg.
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