Question

calculate mass of Na2CO3 which will have the same number of molecules as contained in 12.3 g of MgSO4.7H2O

Answer 1

Answer:

7H2O is 24+32+64+7(18)=246 gram. No of moles= 12.3/246=0.05moles. As per the question moles of Na2CO3 is 0.05 moles. Molecular mass of Na2CO3 is 46+12+48= 160 gram