Question

calculate mass of NaOH required to complete neutralize 49mg of H2SO4​

Answer 1

Answer: answer is attached below

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Answer 2

Answer:

2NaOH +H2SO4 >> 2H20 +Na2SO4

it means one mole of h2so4 is neutralised by 2 moles of naoh

molecular mass of h2so4=2+32+64=98

moles of H2so4 in the reaction=0.049/98=0.0005

this means that moles of NaOH required =2*0.5=0.001mole

now one mole of NaOH is formed by

23+16+1=40 grams of naoh

therefore 0.001 mole will.be formed by

0.040grams or 40 mg

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