calculate mass of oxalic acid which is required to be added completely with 31.6g of KMNO4. Also calculate volume of co2 produced at STP.
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Answer:
2MnO
4
−
+5C
2
O
4
2−
+16H
+
⟶2Mn
2+
+10CO
2
+8H
2
O
20 ml of 0.1 M KMnO
4
contains 0.1×0.020 moles of KMnO
4
i.e, 0.002 moles of KMnO
4
(A) 120 mL of 0.25M H
2
C
2
O
4
contains 0.25×0.12 moles of H
2
C
2
O
4
i.e, 0.03 moles of H
2
C
2
O
4
(B) 50 mL of 0.10 M H
2
C
2
O
4
contains 0.05×0.1 moles of H
2
C
2
O
4
i.e, 0.005 moles of H
2
C
2
O
4
(C) 25 mL of 0.20 M H
2
C
2
O
4
contains 0.005 moles of H
2
C
2
O
4
(D) 50 mL of 0.20 M H
2
C
2
O
4
contains 0.01 moles of H
2
C
2
O
4
By stiochimetry, 2 moles of KMnO
4
is equivalent to 5 moles of H
2
C
2
O
4
Therefore, 0.002 moles of KMnO
4
is equivalent to 0.005 moles of H
2
C
2
O
4
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