Question

Calculate mass of oxygen required when 3.2
grams of CH4 is in combustion with oxygen​

Answer 1

Answer:

mass of Methane = 16 g

mass of 2 molecules of oxygen = 64 g

The equation shows that 16 g of methane requires 64 g of Oxygen

1.61.6g of methane requires 64×1.6/16 = 6.4 g of oxygen

Explanation:

I hope it is helpful to you ☺☺