Chemistry, asked by haripatel81289p6q68i, 1 year ago

Calculate mass of photon having 3.6angstrom wavelength.
Please solve it.

Answers

Answered by Dishay
4
Lambda=3.6Å=3.6*10-10m 

Velocity of photon =velocity of light

M=h/lambda*v =6.626*10-34js/(3.6*10-10m)(3*10 8 m/s)

=6.135*10 -29 Kg

2 years ago



lamda = 3.6 angstrom =  3.6 x 10^-10 m

velocity of photon = velocity of light 

m = h/lamda*v ( from de-brogile’s equation)

m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8

m = 6.626 x 10^-32/10.8

m = 0.6135 x 10^-32

m = 6.135 x 10^-33 kg

 

one year ago



We know that wavelength=Planck`s constant/mass ×velocityOr lambda=h/mvm=h/lambda×v=6.63×10^-34 / 3.6×10^-10 × 3×10^8=6.139 × 10^-33

8 months ago



We know that wavelength=Planck`s constant/mass ×velocityOr lambda=h/mvm=h/lambda×v=6.63×10^-34 / 3.6×10^-10 × 3×10^8=6.139 × 10^-33


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Answered by mohitgurung626
1
here u go ...I wrote it myself since it was gr8 question.........
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