Calculate mass of photon having 3.6angstrom wavelength.
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Answered by
4
Lambda=3.6Å=3.6*10-10m
Velocity of photon =velocity of light
M=h/lambda*v =6.626*10-34js/(3.6*10-10m)(3*10 8 m/s)
=6.135*10 -29 Kg
2 years ago

lamda = 3.6 angstrom = 3.6 x 10^-10 m
velocity of photon = velocity of light
m = h/lamda*v ( from de-brogile’s equation)
m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8
m = 6.626 x 10^-32/10.8
m = 0.6135 x 10^-32
m = 6.135 x 10^-33 kg
one year ago

We know that wavelength=Planck`s constant/mass ×velocityOr lambda=h/mvm=h/lambda×v=6.63×10^-34 / 3.6×10^-10 × 3×10^8=6.139 × 10^-33
8 months ago

We know that wavelength=Planck`s constant/mass ×velocityOr lambda=h/mvm=h/lambda×v=6.63×10^-34 / 3.6×10^-10 × 3×10^8=6.139 × 10^-33
Velocity of photon =velocity of light
M=h/lambda*v =6.626*10-34js/(3.6*10-10m)(3*10 8 m/s)
=6.135*10 -29 Kg
2 years ago

lamda = 3.6 angstrom = 3.6 x 10^-10 m
velocity of photon = velocity of light
m = h/lamda*v ( from de-brogile’s equation)
m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8
m = 6.626 x 10^-32/10.8
m = 0.6135 x 10^-32
m = 6.135 x 10^-33 kg
one year ago

We know that wavelength=Planck`s constant/mass ×velocityOr lambda=h/mvm=h/lambda×v=6.63×10^-34 / 3.6×10^-10 × 3×10^8=6.139 × 10^-33
8 months ago

We know that wavelength=Planck`s constant/mass ×velocityOr lambda=h/mvm=h/lambda×v=6.63×10^-34 / 3.6×10^-10 × 3×10^8=6.139 × 10^-33
Dishay:
PLEASE mark as brainlest
Answered by
1
here u go ...I wrote it myself since it was gr8 question.........
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