calculate mass of silver that contains same number of atoms as present in 5.6 g of iron
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no of atoms ofFe = no of atoms of Agavogadro no x (mass of Fe) / (atomic massof Fe) = avogadro no x (mass of Ag) / (atomic mass of Ag)6.02 x 1023 x 5.6 / 56 =6.02 x 1023 x mass of Ag / 108mass of Ag = 108 x 5,6 / 56mass of Ag = 10.8 g
hope it helped if it helped mrk my answer as best please :)
hope it helped if it helped mrk my answer as best please :)
akshara123:
no of atoms ofFe = no of atoms of Agavogadro no x (mass of Fe) / (atomic massof Fe) = avogadro no x (mass of Ag) / (atomic mass of Ag)6.02 x 1023 x 5.6 / 56 =6.02 x 1023 x mass of Ag / 108mass of Ag = 108 x 5,6 / 56mass of Ag = 10.8 g
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