Question

Calculate mass of solute in 250 cm^3 of 1N H2SO4

Answer 1

Explanation:

So, 250 cm³ 0.5 N H2So4 has (250×0.5) ÷1000=0.125 equivalent H2So4.

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Answer 2

Answer:

6.125 gram of  present in 250 cm³ of seminormal solution​

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

normality of solution= given mass * 1000/equivalent mass * volume of solution( in ml)

We are given:

Normality = 0.5 N

Given mass of  = x g

Equivalent mass of  H2SO4= Molecular mass /basicity= 98/2= g/eq  

Volume of solution = 250 ml  

Putting values in above equation, we get:

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Explanation:

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