Calculate mass % of solution prepared using 12g NaOH & 90g water Also calculate
its molality
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mass %= 12/102×100
= 11.8 %
no. of mole NaOH = 12/ molars mass= 0.3
molality= mole of solute/ mass of solutions in kg
= 0.3/0.09(kg)
= 33.3 m
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