calculate mass percentage of atoms present in c2h5oh
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Explanation:
C2H5OH
weight=12(2)+5(1)+(16)+(1)=46
°/•C=12/46×100=26 percent
°/•H=1/46×100=2.17 percent
°/•O=16/46×100=34.7 percent
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Answer:
Answer is correct 90%
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