Question

calculate mass percentage of benzene (C6H6) dissolved in 122 g of carbon tetrachloride (CCl4)​

Answer 1

Answer:

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Explanation:

Given that,

Mass of benzene (C6H6) = 22 g

Mass of carbon tetrachloride (CCl4) = 122 g

Mass of solution dissolved = 22+122 = 144 g

Then, we have to find,

Mass percentage of benzene = ?

Mass percentage of carbon tetrachloride = ?

Now, using the formula,

(Mass percentage of benzene = Mads of benzene)/ (Mass of benzene + Mass of carbon tetrachloride)×100

Mass percentage of benzene = 22/22+122×100

= 22/144×100

= 1100/72

= 15.2%

Mass percentage of benzene = 15.2%

Mass percentage of carbon tetrachloride= 100-15.2% = 84.8%

Mass percentage of CCl4 = 84.8%