Question

calculate mass volume and number of molecules of hydrogen gas liberated of 130g of zinc reacts with hydrochloric acid​

Answer 1

Answer:1

mol

of  

Zn

has mass of  

65.39

g

.

The amount of  

Zn

is  

2.5

g

65.39

g/mol

=

0.038

mol

.

The amount of  

H

2

produced is the same as the amount of  

Zn

consumed  

(

0.038

mol

)

.

1

mol

of ideal gas will occupy  

22.4

L

at STP.

The  

H

2

will occupy  

0.038

mol

×

22.4

L/mol

=

0.86

L

.

Explanation: