Question

calculate max height attained by ball thrown upward with 49m/s​

Answer 1

Answer:

Given Initial velocity of ball, u=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s^2

holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

v2 −u 2 =2aH

0−(49)2 =2×(−9.8)×H

⟹H=122.5 m

hope it will help you....